The Riemann zeta function and tuning/Vector's derivation: Difference between revisions

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$$ \mu_{d}\left(\sigma, x\right)=\sum_{k=1}^{\infty}k^{ix}{k^{-\sigma} $$
$$ \mu_{d}\left(\sigma, x\right)=\sum_{k=1}^{\infty}k^{ix}{k^{-\sigma} $$
so


$$ \mu_{d}\left(\sigma, x\right)=\sum_{k=1}^{\infty}k^{-\sigma+ix} $$
$$ \mu_{d}\left(\sigma, x\right)=\sum_{k=1}^{\infty}k^{-\sigma+ix} $$