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Talk:K*N subgroups: Difference between revisions

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Mike Battaglia (talk | contribs)
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m Text replacement - "'''All discussion below is archived from the Wikispaces export in its original unaltered form.'''" to "'''All discussion below is archived from the Wikispaces export in its original unaltered form.''' <span style="color:#800000">''...
WikispacesArchive>Mike Battaglia
m Text replacement - "'''All discussion below is archived from the Wikispaces export in its original unaltered form.'''" to "'''All discussion below is archived from the Wikispaces export in its original unaltered form.''' <span style="color:#800000">''...
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= ARCHIVED WIKISPACES DISCUSSION BELOW =
{{WSArchiveLink}}
'''All discussion below is archived from the Wikispaces export in its original unaltered form.'''
 
<span style="color:#800000">'''PLEASE MAKE ANY NEW COMMENTS <u>ABOVE</u> THIS SECTION.'''</span> Anything below here is for archival purposes only.
 
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== example ==
Hello Gene Ward Smith,
 
can you please give a simple example? Thanks :)
 
- '''xenwolf''' May 29, 2011, 12:42:46 PM UTC-0700
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Basically, you take the val of k*N-edo, get the primes with mappings divisible by k (integer steps of N-edo), and for those that don't, find some power, product, or quotient that does. For the 2*N subgroup you'll usually square the first prime mapped to an odd number of 2*N-edo steps and multiply the prime by any other prime mapped to an odd number of steps of 2*N-edo.
 
- '''bootmii''' December 22, 2016, 04:30:17 PM UTC-0800
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