Tuning map: Difference between revisions
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A '''tuning map''' represents the tuning of a [[regular temperament]]. It can take a vector representation of an interval ([[monzo]]) as input and outputs its pitch, usually measured in cents or octaves. A tuning map has one entry for each [[formal prime]] of the temperament, giving its size in cents or octaves. | A '''tuning map''' represents the tuning of a [[regular temperament]]. It can take a vector representation of an interval ([[monzo]]) as input and outputs its pitch, usually measured in cents or octaves. A tuning map has one entry for each [[formal prime]] of the temperament, giving its size in cents or octaves. | ||
== | == Generator tuning map == | ||
A '''generator tuning map''' is like a (temperament) tuning map, but each entry gives the size in cents or octaves of a different [[generator]], rather than of a formal prime. | |||
From the generator tuning map | From the generator tuning map <math>\textbf{g}</math> and the mapping <math>M</math>, we can obtain the tuning map <math>\textbf{t}</math> as <math>\textbf{g}.M</math>. | ||
< | == Example == | ||
Consider meantone temperament, with the mapping {{ket|{{map| 1 1 0 }} {{map| 0 1 4 }} }}. Temperaments, as represented by mappings, remain abstract; while this mapping does convey that the generators are ~2/1 and ~3/2, it does not specify exact tunings for those approximations. One example tuning would be quarter-comma meantone, where the octave is pure and the perfect fifth is 5<sup>1/4</sup>; this gives a generator tuning map of {{map| 1200.000 696.578 }}. | |||
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The tuning map from | The tuning map from <math>\textbf{g}</math> = {{map| 1200.000 696.578 }} and <math>M</math> = {{ket|{{map| 1 1 0 }} {{map| 0 1 4 }} }} is <math>\textbf{t}</math> = {{map| 1200.000 1896.578 2786.314 }}. | ||
So, to answer the question, "how many cents is the approximation of the interval 16/15 in quarter-comma meantone?" we use the dot product to map 16/15's prime count vector {{vector| 4 -1 -1 }} via the tuning map given above, 4×1200.000 + (-1)×1896.578 + (-1)×2786.314 = 117.108 cents. | So, to answer the question, "how many cents is the approximation of the interval 16/15 in quarter-comma meantone?" we use the dot product to map 16/15's prime count vector {{vector| 4 -1 -1 }} via the tuning map given above, 4×1200.000 + (-1)×1896.578 + (-1)×2786.314 = 117.108 cents. | ||