Comma basis: Difference between revisions

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This is a basic introduction to this concept. For a more mathematical take, see [[dual list]].  
This is a basic introduction to this concept. For a more mathematical take, see [[dual list]].  


A '''comma-basis''' is a basis for the [[wikipedia:Kernel_(linear_algebra)|null-space]] (sometimes also called the "kernel") of a [[regular temperament|temperament]]. It consists of <span><math>n</math></span> [[Wikipedia:Linear_independence|linearly independent]] vectors, where <span><math>n</math></span> is the [[nullity]], each one representing a [[comma]] that is [[tempered out]].  
A '''comma-basis''' is a basis for the [[wikipedia:Kernel_(linear_algebra)|null-space]] (sometimes also called the "kernel") of a [[regular temperament|temperament]]. It consists of <math>n</math> [[Wikipedia:Linear_independence|linearly independent]] vectors, where <math>n</math> is the [[nullity]], each one representing a [[comma]] that is [[tempered out]].  


Linear independence means that no comma can be found as the sum of any multiples of the other commas. For example, consider the set of three commas 81/80, 126/125, and 225/224. As vectors those are {{vector|-4 4 -1 0}}, {{vector|1 2 -3 1}}, and {{vector|-5 2 2 -1}}. Notice that the third comma is actually the difference between the other two; {{vector|-4 4 -1 0}} - {{vector|1 2 -3 1}} = {{vector|-5 2 2 -1}}, or as cents, 21.51¢ - 13.80¢ = 7.71¢. So, if two of these three commas are ever tempered out (mapped to 0¢), then the third one necessarily is also tempered out. Therefore, we only need to pick two of these commas to put in our comma-basis; the third one would be implied.
Linear independence means that no comma can be found as the sum of any multiples of the other commas. For example, consider the set of three commas 81/80, 126/125, and 225/224. As vectors those are {{vector|-4 4 -1 0}}, {{vector|1 2 -3 1}}, and {{vector|-5 2 2 -1}}. Notice that the third comma is actually the difference between the other two; {{vector|-4 4 -1 0}} - {{vector|1 2 -3 1}} = {{vector|-5 2 2 -1}}, or as cents, 21.51¢ - 13.80¢ = 7.71¢. So, if two of these three commas are ever tempered out (mapped to 0¢), then the third one necessarily is also tempered out. Therefore, we only need to pick two of these commas to put in our comma-basis; the third one would be implied.