Logarithmic approximants: Difference between revisions

CompactStar (talk | contribs)
Sintel bot (talk | contribs)
Fix <math> environments for MathJax v4 (align->aligned, etc.)
 
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:<math>
:<math>
\begin{align}  
\begin{aligned}  
v &= \frac{n-d}{n+d} \\
v &= \frac{n-d}{n+d} \\
&= \text{(frequency difference) / (frequency sum)} \\
&= \text{(frequency difference) / (frequency sum)} \\
&= \frac{1}{2} \text{(frequency difference) / (mean frequency)}
&= \frac{1}{2} \text{(frequency difference) / (mean frequency)}
\end{align}  
\end{aligned}  
</math>
</math>


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<math>
<math>
\begin{align}
\begin{aligned}
v[-J] &= -v[J] \\
v[-J] &= -v[J] \\
v[J_1 +J_2] &= \frac{v_1+v_2}{1+v_1 v_2}
v[J_1 +J_2] &= \frac{v_1+v_2}{1+v_1 v_2}
\end{align}
\end{aligned}
</math>
</math>


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:<math>
:<math>
\begin{align}
\begin{aligned}
q(r) &= \frac{1}{2} \left( r^{\frac{1}{2}} - r^{-\frac{1}{2}} \right) \\
q(r) &= \frac{1}{2} \left( r^{\frac{1}{2}} - r^{-\frac{1}{2}} \right) \\
    &= \frac{1}{2} \left( e^{J} - e^{-J}    \right) \\
    &= \frac{1}{2} \left( e^{J} - e^{-J}    \right) \\
    &= \sinh{J} \\
    &= \sinh{J} \\
    &= J + \frac{1}{3!} J^3 + \frac{1}{5!} J^5 + \ldots
    &= J + \frac{1}{3!} J^3 + \frac{1}{5!} J^5 + \ldots
\end{align}
\end{aligned}
</math>
</math>


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:<math>
:<math>
\begin{align}
\begin{aligned}
v &= \tanh{J}, \; q = \sinh{J}, \; \frac{q}{v} = \cosh{J} \\
v &= \tanh{J}, \; q = \sinh{J}, \; \frac{q}{v} = \cosh{J} \\
\sqrt{r} &= e^J = q(\frac{1}{v} + 1) \\
\sqrt{r} &= e^J = q(\frac{1}{v} + 1) \\
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\frac {q[J_2 + J_1]}{q[J_2 - J_1]} &= \frac{v_2+v_1}{v_2-v_1} \\
\frac {q[J_2 + J_1]}{q[J_2 - J_1]} &= \frac{v_2+v_1}{v_2-v_1} \\
q[J_2 + J_1] q[J_2 - J_1] &= q_2^2 - q_1^2 \\
q[J_2 + J_1] q[J_2 - J_1] &= q_2^2 - q_1^2 \\
\end{align}
\end{aligned}
</math>
</math>


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:<math>
:<math>
\begin{align}
\begin{aligned}
\frac{\text{octave}}{\text{large tone}} &\approx \frac{q[F+f]}{q[F-f]} \\
\frac{\text{octave}}{\text{large tone}} &\approx \frac{q[F+f]}{q[F-f]} \\
&= \frac{v[F] + v[f]}{v[F] - v[f]} \\  
&= \frac{v[F] + v[f]}{v[F] - v[f]} \\  
&= \frac{1/5 + 1/7}{1/5 - 1/7} = 6
&= \frac{1/5 + 1/7}{1/5 - 1/7} = 6
\end{align}
\end{aligned}
</math>
</math>


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:<math>
:<math>
\begin{align}
\begin{aligned}
b(J_1,J_2) &\approx \left( \frac{1}{3} \left(q_2^2 - q_1^2\right) - \frac{2}{15} \left( q_2^4 - q_1^4 \right) \right) b_m \\
b(J_1,J_2) &\approx \left( \frac{1}{3} \left(q_2^2 - q_1^2\right) - \frac{2}{15} \left( q_2^4 - q_1^4 \right) \right) b_m \\
&= \frac{1}{3} \left( q_2^2 - q_1^2 \right) \left( 1 - \frac{2}{5} \left(q_1^2 + q_2^2\right) \right) b_m
&= \frac{1}{3} \left( q_2^2 - q_1^2 \right) \left( 1 - \frac{2}{5} \left(q_1^2 + q_2^2\right) \right) b_m
\end{align}
\end{aligned}
</math>
</math>