Tenney–Euclidean temperament measures: Difference between revisions

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We can consider '''TE error''' to be a weighted average of the error of each prime harmonics in TE tuning. Multiplying it by 1200, we get a figure with values in cents.  
We can consider '''TE error''' to be a weighted average of the error of each prime harmonics in TE tuning. Multiplying it by 1200, we get a figure with values in cents.  


By Graham Breed's definition, TE error may be accessed via [[Tenney–Euclidean tuning|TE tuning map]]. If T is the tuning map, then the TE error ''G'' can be found by
By Graham Breed's definition, TE error may be accessed via [[Tenney–Euclidean tuning|TE tuning map]]. If ''T'' is the tuning map, then the TE error ''G'' can be found by


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<math>\displaystyle
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By Gene Ward Smith's definition, the TE error is derived from the relationship of TE simple badness and TE complexity. We denote this definition of TE error Ψ.  
By Gene Ward Smith's definition, the TE error is derived from the relationship of TE simple badness and TE complexity. We denote this definition of TE error Ψ.  


From the ratio {{nowrap|(‖''J'' ∧ ''M''‖/‖''M''‖)<sup>2</sup>}} we obtain {{nowrap|{{sfrac|({{subsup||''r'' + 1|''n''}})|''n''({{subsup||''r''|''n''}})}} {{=}} {{sfrac|''n'' − ''r''|''n''(''r'' + 1)}}}}. If we take the ratio of this for rank one with this for rank ''r'', the ''n'' cancels, and we get {{nowrap|{{sfrac|''n'' − 1|2}} · {{sfrac|''r'' + 1|''n'' − ''r''}} {{=}} {{sfrac|(''r'' + 1)(''n'' − 1)|2(''n'' − ''r'')}}}}. It follows that dividing TE error by the square root of this ratio gives a constant of proportionality such that if Ψ is the TE error of a rank-''r'' temperament then
From the ratio {{nowrap|(‖''J'' ∧ ''M''‖ / ‖''M''‖)<sup>2</sup>}} we obtain {{nowrap|{{sfrac|({{subsup||''r'' + 1|''n''}})|''n''({{subsup||''r''|''n''}})}} {{=}} {{sfrac|''n'' − ''r''|''n''(''r'' + 1)}}}}. If we take the ratio of this for rank one with this for rank ''r'', the ''n'' cancels, and we get {{nowrap|{{sfrac|''n'' − 1|2}} · {{sfrac|''r'' + 1|''n'' − ''r''}} {{=}} {{sfrac|(''r'' + 1)(''n'' − 1)|2(''n'' − ''r'')}}}}. It follows that dividing TE error by the square root of this ratio gives a constant of proportionality such that if Ψ is the TE error of a rank-''r'' temperament then


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<math>\displaystyle