Würschmidt comma: Difference between revisions
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It is the amount by which an octave-reduced stack of eight major thirds falls short of a perfect fifth: <math>\frac{1}{4}\left(\frac{5}{4}\right)^{8}\left(\frac{393216}{390625}\right)=\frac{3}{2}</math>, which comes from 5/4 being a convergent in the continued fraction of <math>\sqrt[8]{6}</math>. | It is the amount by which an octave-reduced stack of eight major thirds falls short of a perfect fifth: <math>\frac{1}{4}\left(\frac{5}{4}\right)^{8}\left(\frac{393216}{390625}\right)=\frac{3}{2}</math>, which comes from 5/4 being a convergent in the continued fraction of <math>\sqrt[8]{6}</math>. | ||
It is also equal to the difference between the lesser diesis and the magic comma, <math>\frac{128}{125}/\frac{3125}{3072}</math> | It is also equal to the difference between the lesser diesis and the magic comma, <math>\frac{128}{125}/\frac{3125}{3072}</math>, and the difference between seven major thirds and 24/5 (i.e. 6/5 plus two octaves). In other words, <math>\frac{1}{4}\left(\frac{5}{4}\right)^{7}\left(\frac{393216}{390625}\right)=\frac{6}{5}</math>. | ||
Tempering it out leads to the [[würschmidt family]] of temperaments. As in [[meantone]], it implies that 3/2 will be tempered flat and/or 5/4 will be tempered sharp, and therefore 6/5 will be tempered flat. | Tempering it out leads to the [[würschmidt family]] of temperaments. As in [[meantone]], it implies that 3/2 will be tempered flat and/or 5/4 will be tempered sharp, and therefore 6/5 will be tempered flat. | ||