Kite's thoughts on pergens: Difference between revisions

Wikispaces>TallKite
**Imported revision 625221961 - Original comment: **
Wikispaces>TallKite
**Imported revision 625289603 - Original comment: **
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<h2>IMPORTED REVISION FROM WIKISPACES</h2>
<h2>IMPORTED REVISION FROM WIKISPACES</h2>
This is an imported revision from Wikispaces. The revision metadata is included below for reference:<br>
This is an imported revision from Wikispaces. The revision metadata is included below for reference:<br>
: This revision was by author [[User:TallKite|TallKite]] and made on <tt>2018-01-22 20:23:25 UTC</tt>.<br>
: This revision was by author [[User:TallKite|TallKite]] and made on <tt>2018-01-24 02:12:11 UTC</tt>.<br>
: The original revision id was <tt>625221961</tt>.<br>
: The original revision id was <tt>625289603</tt>.<br>
: The revision comment was: <tt></tt><br>
: The revision comment was: <tt></tt><br>
The revision contents are below, presented both in the original Wikispaces Wikitext format, and in HTML exactly as Wikispaces rendered it.<br>
The revision contents are below, presented both in the original Wikispaces Wikitext format, and in HTML exactly as Wikispaces rendered it.<br>
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Simplify by dividing by b to get (P8/m, (q - ap, -m) / qm) = (P8/m, (a',b')/n')
Simplify by dividing by b to get (P8/m, (q - ap, -m) / qm) = (P8/m, (a',b')/n')
Can b' be reduced by simplifying further?
Can b' be reduced by simplifying further?
No, because GCD (a', b') = GCD (q - ap, -bp) = r
Let r = GCD (a', b') = GCD (q - ap, -bp)
Since a and b are coprime, GCD (-ap, -bp) = p
GCD (q - ap, p) = GCD (q, p) = 1
Since GCD (p, q) = 1
Therefore r &lt;= b, and r = GCD (q - ap, b)
b' = -m, therefore m = |b'|, and the unreduced pergen is explicitly false
[//unfinished proof//]
Therefore the original pergen is a false double


To prove: alternate true/false test
To prove: alternate true/false test
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(P8/m, (a,b)/n) unreduced is (P8/m, (n-am, -bm) / mn) = (P8/m, (a',b')/n')
(P8/m, (a,b)/n) unreduced is (P8/m, (n-am, -bm) / mn) = (P8/m, (a',b')/n')
Simplify using b = GCD (m,n): a' = (n-am)/b, b' = -m, and n' = mn/b
Simplify using b = GCD (m,n): a' = (n-am)/b, b' = -m, and n' = mn/b
[//needs more work//]
|b'| = m, so the unreduced pergen is explicitly false, and the test works
|b'| = m, so the unreduced pergen is explicitly false, and the test works


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Simplify by dividing by b to get (P8/m, (q - ap, -m) / qm) = (P8/m, (a',b')/n')&lt;br /&gt;
Simplify by dividing by b to get (P8/m, (q - ap, -m) / qm) = (P8/m, (a',b')/n')&lt;br /&gt;
Can b' be reduced by simplifying further?&lt;br /&gt;
Can b' be reduced by simplifying further?&lt;br /&gt;
No, because GCD (a', b') = GCD (q - ap, -bp) = r&lt;br /&gt;
Let r = GCD (a', b') = GCD (q - ap, -bp)&lt;br /&gt;
Since a and b are coprime, GCD (-ap, -bp) = p&lt;br /&gt;
GCD (q - ap, p) = GCD (q, p) = 1&lt;br /&gt;
Since GCD (p, q) = 1&lt;br /&gt;
Therefore r &amp;lt;= b, and r = GCD (q - ap, b)&lt;br /&gt;
b' = -m, therefore m = |b'|, and the unreduced pergen is explicitly false&lt;br /&gt;
[&lt;em&gt;unfinished proof&lt;/em&gt;]&lt;br /&gt;
Therefore the original pergen is a false double&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
To prove: alternate true/false test&lt;br /&gt;
To prove: alternate true/false test&lt;br /&gt;
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(P8/m, (a,b)/n) unreduced is (P8/m, (n-am, -bm) / mn) = (P8/m, (a',b')/n')&lt;br /&gt;
(P8/m, (a,b)/n) unreduced is (P8/m, (n-am, -bm) / mn) = (P8/m, (a',b')/n')&lt;br /&gt;
Simplify using b = GCD (m,n): a' = (n-am)/b, b' = -m, and n' = mn/b&lt;br /&gt;
Simplify using b = GCD (m,n): a' = (n-am)/b, b' = -m, and n' = mn/b&lt;br /&gt;
[&lt;em&gt;needs more work&lt;/em&gt;]&lt;br /&gt;
|b'| = m, so the unreduced pergen is explicitly false, and the test works&lt;br /&gt;
|b'| = m, so the unreduced pergen is explicitly false, and the test works&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;