Fokker block: Difference between revisions

Wikispaces>genewardsmith
**Imported revision 151755221 - Original comment: **
Wikispaces>genewardsmith
**Imported revision 151756699 - Original comment: **
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<h2>IMPORTED REVISION FROM WIKISPACES</h2>
<h2>IMPORTED REVISION FROM WIKISPACES</h2>
This is an imported revision from Wikispaces. The revision metadata is included below for reference:<br>
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: This revision was by author [[User:genewardsmith|genewardsmith]] and made on <tt>2010-07-06 21:41:19 UTC</tt>.<br>
: This revision was by author [[User:genewardsmith|genewardsmith]] and made on <tt>2010-07-06 21:55:32 UTC</tt>.<br>
: The original revision id was <tt>151755221</tt>.<br>
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===First definition of a Fokker block===  
===First definition of a Fokker block===  
Now set P = v1(2) and choose two sets of n positive integers e1, ..., en, and a1, ...., an with e1+e2+...+en = P and ak &lt; P; and let ti = log2(ci), choosing the e1 so that e1*t1+e2*t2+...+en*tn=1. Now define a function on the integers by
Let us set ei = vi(2), and also P = e1 = v1(2), and choose n positive integers a1, ...., an with ak &lt; P. Let ti = log2(ci), so that e1*t1+e2*t2+...+en*tn=1. Now define a function on the integers by


S[i] = floor((e1*i + a1)/P)*t1 + ... + floor((en*i + an)/P)*tn
S[i] = floor((e1*i + a1)/P)*t1 + ... + floor((en*i + an)/P)*tn


Here floor(x) is the [[http://en.wikipedia.org/wiki/Floor_and_ceiling_functions|floor function]], the [[http://en.wikipedia.org/wiki/Quasiperiodic_function|quasiperiodic function]] returning the largest integer less than or equal to x. When i=0, since ak &lt; N each term is 0 and so S[0] = 0. Since for integer j, floor(x+j) = floor(x) + j, we have
Here floor(x) is the [[http://en.wikipedia.org/wiki/Floor_and_ceiling_functions|floor function]], the [[http://en.wikipedia.org/wiki/Quasiperiodic_function|quasiperiodic function]] returning the largest integer less than or equal to x. When i=0, since ak &lt; P each term is 0 and so S[0] = 0. Since for integer j, floor(x+j) = floor(x) + j, we have


S[i + P] = S[i] + e1*t1 + e2*t2 + ... + en*tn = S[i] + 1
S[i + P] = S[i] + e1*t1 + e2*t2 + ... + en*tn = S[i] + 1
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&lt;br /&gt;
&lt;br /&gt;
&lt;!-- ws:start:WikiTextHeadingRule:2:&amp;lt;h3&amp;gt; --&gt;&lt;h3 id="toc1"&gt;&lt;a name="x--First definition of a Fokker block"&gt;&lt;/a&gt;&lt;!-- ws:end:WikiTextHeadingRule:2 --&gt;First definition of a Fokker block&lt;/h3&gt;
&lt;!-- ws:start:WikiTextHeadingRule:2:&amp;lt;h3&amp;gt; --&gt;&lt;h3 id="toc1"&gt;&lt;a name="x--First definition of a Fokker block"&gt;&lt;/a&gt;&lt;!-- ws:end:WikiTextHeadingRule:2 --&gt;First definition of a Fokker block&lt;/h3&gt;
  Now set P = v1(2) and choose two sets of n positive integers e1, ..., en, and a1, ...., an with e1+e2+...+en = P and ak &amp;lt; P; and let ti = log2(ci), choosing the e1 so that e1*t1+e2*t2+...+en*tn=1. Now define a function on the integers by&lt;br /&gt;
  Let us set ei = vi(2), and also P = e1 = v1(2), and choose n positive integers a1, ...., an with ak &amp;lt; P. Let ti = log2(ci), so that e1*t1+e2*t2+...+en*tn=1. Now define a function on the integers by&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
S[i] = floor((e1*i + a1)/P)*t1 + ... + floor((en*i + an)/P)*tn&lt;br /&gt;
S[i] = floor((e1*i + a1)/P)*t1 + ... + floor((en*i + an)/P)*tn&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Here floor(x) is the &lt;a class="wiki_link_ext" href="http://en.wikipedia.org/wiki/Floor_and_ceiling_functions" rel="nofollow"&gt;floor function&lt;/a&gt;, the &lt;a class="wiki_link_ext" href="http://en.wikipedia.org/wiki/Quasiperiodic_function" rel="nofollow"&gt;quasiperiodic function&lt;/a&gt; returning the largest integer less than or equal to x. When i=0, since ak &amp;lt; N each term is 0 and so S[0] = 0. Since for integer j, floor(x+j) = floor(x) + j, we have&lt;br /&gt;
Here floor(x) is the &lt;a class="wiki_link_ext" href="http://en.wikipedia.org/wiki/Floor_and_ceiling_functions" rel="nofollow"&gt;floor function&lt;/a&gt;, the &lt;a class="wiki_link_ext" href="http://en.wikipedia.org/wiki/Quasiperiodic_function" rel="nofollow"&gt;quasiperiodic function&lt;/a&gt; returning the largest integer less than or equal to x. When i=0, since ak &amp;lt; P each term is 0 and so S[0] = 0. Since for integer j, floor(x+j) = floor(x) + j, we have&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
S[i + P] = S[i] + e1*t1 + e2*t2 + ... + en*tn = S[i] + 1&lt;br /&gt;
S[i + P] = S[i] + e1*t1 + e2*t2 + ... + en*tn = S[i] + 1&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Hence S satisfies the conditions for being a &lt;a class="wiki_link" href="/Periodic%20scale"&gt;periodic scale&lt;/a&gt;, and since our unit of measurement is the octave, ie we are using log base two to define intervals, the repetition interval 1 represents an octave. This gives us our first definition of Fokker block.&lt;/body&gt;&lt;/html&gt;</pre></div>
Hence S satisfies the conditions for being a &lt;a class="wiki_link" href="/Periodic%20scale"&gt;periodic scale&lt;/a&gt;, and since our unit of measurement is the octave, ie we are using log base two to define intervals, the repetition interval 1 represents an octave. This gives us our first definition of Fokker block.&lt;/body&gt;&lt;/html&gt;</pre></div>