Plücker coordinates: Difference between revisions

Sintel (talk | contribs)
Sintel (talk | contribs)
fix mathjax errors
 
Line 20: Line 20:
The Plücker map takes a temperament and embeds it into a projective space by taking the wedge product of the basis vectors:
The Plücker map takes a temperament and embeds it into a projective space by taking the wedge product of the basis vectors:
:<math>
:<math>
\begin{align}
\begin{aligned}
\iota: \mathrm{Gr} (k, n)  
\iota: \mathrm{Gr} (k, n)  
& \to \mathbf{P}\left(\Lambda^{k} \, \mathbb{R}^n \right) \\
& \to \mathbf{P}\left(\Lambda^{k} \, \mathbb{R}^n \right) \\
\operatorname {span} (m_1, \ldots, m_k)  
\operatorname {span} (m_1, \ldots, m_k)  
& \mapsto \left[ m_1 \wedge \ldots \wedge m_k \right] \, .
& \mapsto \left[ m_1 \wedge \ldots \wedge m_k \right] \, .
\end{align}
\end{aligned}
</math>
</math>


Line 38: Line 38:
An element <math>M</math> spanned by two lines <math>x, y</math>, can be represented as the matrix
An element <math>M</math> spanned by two lines <math>x, y</math>, can be represented as the matrix
:<math>
:<math>
\begin{equation}
\begin{bmatrix}
\begin{bmatrix}
x_{1} & x_{2} & x_{3} & x_{4} \\
x_{1} & x_{2} & x_{3} & x_{4} \\
y_{1} & y_{2} & y_{3} & y_{4}
y_{1} & y_{2} & y_{3} & y_{4}
\end{bmatrix} \, .
\end{bmatrix} \, .
\end{equation}
</math>
</math>


Line 60: Line 58:


:<math>
:<math>
\begin{equation}
\iota (M) = \left[ x \wedge y \right] = \left[ p_{12} : p_{13} : p_{14} : p_{23} : p_{24} : p_{34} \right] \, .
\iota (M) = \left[ x \wedge y \right] = \left[ p_{12} : p_{13} : p_{14} : p_{23} : p_{24} : p_{34} \right] \, .
\end{equation}
</math>
</math>


Line 107: Line 103:
The height can be easily computed using the {{w|Gram matrix}}:
The height can be easily computed using the {{w|Gram matrix}}:
:<math>
:<math>
\begin{align}
\begin{aligned}
\mathrm{G}_{ij} &= \left\langle m_i, m_j \right\rangle \\
\mathrm{G}_{ij} &= \left\langle m_i, m_j \right\rangle \\
\sqrt{\det(\mathrm{G})} &= \left\| m_1 \wedge \ldots \wedge m_n \right\| = \left\| X \right\| \, .
\sqrt{\det(\mathrm{G})} &= \left\| m_1 \wedge \ldots \wedge m_n \right\| = \left\| X \right\| \, .
\end{align}
\end{aligned}
</math>
</math>