User talk:Contribution: Difference between revisions

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Line 189:

<pre>

# Enter the values for the X ratio of EDX. Ensure the numerator and denominator differ by 1 or 2.

numerator, denominator = 7, 6

numerator, denominator = 3, 2

# Program

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(pair_1, pair_2) = calculate_complementary_pair(numerator, denominator)

print(f"Successive superparticular complementary pair of {numerator}/{denominator} ~~are~~: {pair_1[0]}/{pair_1[1]} and {pair_2[0]}/{pair_2[1]}")

print(f"Successive superparticular complementary pair of {numerator}/{denominator}: {pair_1[0]}/{pair_1[1]} and {pair_2[0]}/{pair_2[1]}")

# Calculate ratios

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print_mappings(ratio_log_cents, superparticular_complementary_log_cents, numerator, denominator)

</pre>

{{todo|Generalize|inline=1|comment=For example, within ed15/8, pair of superparticulars 5/4 and 3/2 are 15/8 complementary. Within ed21/16, pair of superparticulars 9/8 and 7/6 are 21/16 complementary.

~~Update the code so that it works for any X ratio of EDX without restriction.}}~~

@@ Line 189: / Line 189: @@
 <pre>
 # Enter the values for the X ratio of EDX. Ensure the numerator and denominator differ by 1 or 2.
-numerator, denominator = 7, 6
+numerator, denominator = 3, 2
 # Program
@@ Line 236: / Line 236: @@
 (pair_1, pair_2) = calculate_complementary_pair(numerator, denominator)
-print(f"Successive superparticular complementary pair of {numerator}/{denominator} are: {pair_1[0]}/{pair_1[1]} and {pair_2[0]}/{pair_2[1]}")
+print(f"Successive superparticular complementary pair of {numerator}/{denominator}: {pair_1[0]}/{pair_1[1]} and {pair_2[0]}/{pair_2[1]}")
 # Calculate ratios
@@ Line 249: / Line 249: @@
 print_mappings(ratio_log_cents, superparticular_complementary_log_cents, numerator, denominator)
 </pre>
-{{todo|Generalize|inline=1|comment=For example, within ed15/8, pair of superparticulars 5/4 and 3/2 are 15/8 complementary. Within ed21/16, pair of superparticulars 9/8 and 7/6 are 21/16 complementary.
-Update the code so that it works for any X ratio of EDX without restriction.}}