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| <h2>IMPORTED REVISION FROM WIKISPACES</h2>
| | '''Tempering out''' is what a [[regular temperament]] (including rank-1 temperaments aka [[equal temperament]]s) does to a small interval like a [[comma]]: it makes it disappear, or as some authors put it, ''vanish''.<ref>''Vanish'' is notably used throughout ''[[A Middle Path]]''.</ref> |
| This is an imported revision from Wikispaces. The revision metadata is included below for reference:<br>
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| : This revision was by author [[User:genewardsmith|genewardsmith]] and made on <tt>2011-10-29 20:56:02 UTC</tt>.<br>
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| : The original revision id was <tt>269909704</tt>.<br>
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| : The revision comment was: <tt></tt><br>
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| The revision contents are below, presented both in the original Wikispaces Wikitext format, and in HTML exactly as Wikispaces rendered it.<br>
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| <h4>Original Wikitext content:</h4>
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| <div style="width:100%; max-height:400pt; overflow:auto; background-color:#f8f9fa; border: 1px solid #eaecf0; padding:0em"><pre style="margin:0px;border:none;background:none;word-wrap:break-word;white-space: pre-wrap ! important" class="old-revision-html">**Tempering out** is what a [[regular temperament]] does to a small interval like a [[comma]]: it makes it disappear.
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| For a tone measured as a ratio to "disappear", it must become equal to 1/1, so that multiplying by the ratio doesn't change anything. | | == Overview == |
| | For a tone measured as a ratio to "disappear", it must become equal to 1/1, so that multiplying by the ratio does not change anything. For a tone measured in cents to "disappear", it must become 0 cents, so that adding it does not change anything. |
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| For a tone measured in cents to "disappear", it must become 0 cents, so that adding it doesn't change anything.
| | In both cases, that implies that we are introducing some error into our tunings: where we would use 3, for instance, we use a number slightly larger or smaller than 3. You can introduce error into any prime, and when tempering out a single comma you can choose to leave any given prime pure. In practice, many people leave 2 pure to achieve pure octaves. There are also options to temper the octave, such as [[TOP tuning]]. |
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| In both cases, that implies that we're introducing some error into our tunings: Where we would use 3, for instance, we use a number slightly larger or smaller than 3. You can introduce error into any prime, and when tempering out a single comma you can choose to leave any given prime pure. In practice, many people leave 2 pure to achieve pure octaves.
| | == Tempering together == |
| =Example= | | Two or more [[chord]]s or intervals are said to be ''tempered together'' if the commas that relate all of their corresponding steps are ''tempered out''. If two chords are tempered together, then the representation of each of those chords in the temperament is identical. |
| The syntonic comma is 81/80. That's 3*3*3*3 / 5*2*2*2*2 or, in monzo form, | -4 4 -1 > .
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| 19 EDO tempers out 81/80. (Technically, we should say that 19 EDO tempers out 81/80 when you use the [[patent val]].) You can see this in several ways:
| | For example, in [[meantone]], which tempers out [[81/80]], the chords [[54:64:81]] (with steps 32/27, 81/64) and [[10:12:15]] (with steps 6/5, 5/4) are tempered together. Since {{nowrap|{{Frac|32|27}}{{dot}}{{Frac|81|80}} {{=}} {{Frac|6|5}}}} and {{nowrap|{{Frac|81|64}} {{=}} {{Frac|5|4}}{{dot}}{{Frac|81|80}}}}, equating 81/80 with 1/1 also equates 32/27 with 6/5, and 81/64 with 5/4. |
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| ==1. Counting steps of the val== | | == Example == |
| Because there are no primes larger than 5 in 81/80, we say it's a 5-limit comma. The 5-limit patent val for 19 EDO is < 19 30 44 |. That means that you add 19 steps of 19 EDO to get to 2/1, 30 steps to get closest to 3/1, and 44 steps to get closest to 5/1.
| | The syntonic comma is 81/80. That is {{sfrac|3<sup>4</sup>|2<sup>4</sup> × 5}} or, in [[monzo]] form, {{monzo| -4 4 -1}}. |
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| Note that, because this is an EDO, 19 steps gets you precisely to 2/1. We say that 30 steps of 19 EDO gets you to 3/1, but that's only an approximation. Same with 5/1, etc. This is where the error in the primes gets introduced. Don't worry, though, it's very useful error.
| | 19edo tempers out 81/80. (Technically, we should say that 19edo tempers out 81/80 when you use the [[patent val]].) You can see this in several ways: |
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| Getting to 81 is 3*3*3*3, or, with 19 EDO steps, 30+30+30+30 = 120 steps of 19 EDO.
| | === 1. Counting steps of the val === |
| | Because there are no primes larger than 5 in 81/80, we say it is a 5-limit comma. The 5-limit patent val for 19edo is {{val| 19 30 44 }}. That means that you add 19 steps of 19edo to get to 2/1, 30 steps to get closest to 3/1, and 44 steps to get closest to 5/1. |
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| Getting to 80 is 5*2*2*2*2, or, with 19 EDO steps, 44+19+19+19+19 = 120 steps of 19 EDO.
| | Note that, because this is an edo, 19 steps gets you precisely to 2/1. We say that 30 steps of 19edo gets you to 3/1, but that is only an approximation. Same with 5/1, etc. This is where the error in the primes gets introduced. Don't worry, though, it is very useful error. |
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| Getting to 81/80 means adding the steps needed to get to 81, and subtracting the steps needed to get to 80. 120 steps - 120 steps = 0 steps. | | Getting to 81 is 3×3×3×3, or, with 19edo steps, {{nowrap|30 + 30 + 30 + 30 {{=}} 120}} steps of 19edo. |
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| Applying the monzo to the val (also called getting the "homomorphism") is easier. Multiply the first number in the monzo (which represents the number of 2/1s in the comma) and by the first number in the val (which represents the number of steps it takes to get to 2/1), then multiply the second number in the monzo by the second number in the val, then the third by the third, and add them all together: (-4 * 19) + (4 * 30) + (-1 * 44) = 0 steps.
| | Getting to 80 is 5×2×2×2×2, or, with 19edo steps, {{nowrap|44 + 19 + 19 + 19 + 19 {{=}} 120}} steps of 19edo. |
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| Therefore, adding 81/80 to any interval in 19 EDO means adding 0 steps of 19 EDO to it. In other words, 81/80 is effectively zero: 81/80 is "tempered out".
| | Getting to 81/80 means adding the steps needed to get to 81, and subtracting the steps needed to get to 80. {{nowrap|120 steps − 120 steps {{=}} 0 steps}}. |
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| ==2. Painstakingly doing the math== | | Applying the monzo to the val (also called getting the ''homomorphism'') is easier. Multiply the first number in the monzo (which represents the number of 2/1's in the comma) and by the first number in the val (which represents the number of steps it takes to get to 2/1), then multiply the second number in the monzo by the second number in the val, then the third by the third, and add them all together: {{nowrap|(−4 × 19) + (4 × 30) + (−1 × 44) {{=}} 0 steps}}. |
| We say that 30 steps of 19 EDO gets you to 3/1, but, as we say above, that's an error. One step of 19 EDO is the 19th root of 2, or 2^(1/19), or approximately 1.03715504445. (That's 63.15789474 cents.) If you multiply that by itself 19 times, you get exactly 2. But if you multiply that by itself 30 times, you don't get 3: You get 2.98751792330896. Similarly, multiplying it by 44 steps gets you 4.97877035785607 instead of 5. | | |
| | Therefore, adding 81/80 to any interval in 19edo means adding 0 steps of 19edo to it. In other words, 81/80 is effectively zero: 81/80 is ''tempered out''. |
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| | === 2. Painstakingly doing the math === |
| | We say that 30 steps of 19edo gets you to 3/1, but, as we say above, that is an error. One step of 19edo is the 19th root of 2, or 2<sup>1/19</sup>, or approximately 1.037155. (That is 63.157895 cents.) If you multiply that by itself 19 times, you get exactly 2. But if you multiply that by itself 30 times, you do not get 3: You get 2.987518. Similarly, multiplying it by 44 steps gets you 4.97877 instead of 5. |
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| If we plug in these values into 81/80, we see that 81/80 is tempered out: | | If we plug in these values into 81/80, we see that 81/80 is tempered out: |
| 81/80 = 3*3*3*3 / 5*2*2*2*2 = (3^4) / (5)*(2^4). Substitute our values and you get
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| (2.98751792330896 ^ 4) / (4.97877035785607)*(2^4)
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| = 79.66032573 / (4.97877035785607 * 16)
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| = 79.66032573 / 79.66032573
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| = 1/1.
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| <span style="display: block; height: 1px; left: -40px; overflow: hidden; position: absolute; top: -25px; width: 1px;">
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| || 2.98751792330896 ||
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| </span></pre></div>
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| <h4>Original HTML content:</h4>
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| <div style="width:100%; max-height:400pt; overflow:auto; background-color:#f8f9fa; border: 1px solid #eaecf0; padding:0em"><pre style="margin:0px;border:none;background:none;word-wrap:break-word;width:200%;white-space: pre-wrap ! important" class="old-revision-html"><html><head><title>tempering out</title></head><body><strong>Tempering out</strong> is what a <a class="wiki_link" href="/regular%20temperament">regular temperament</a> does to a small interval like a <a class="wiki_link" href="/comma">comma</a>: it makes it disappear.<br />
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| <br />
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| For a tone measured as a ratio to &quot;disappear&quot;, it must become equal to 1/1, so that multiplying by the ratio doesn't change anything.<br />
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| <br />
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| For a tone measured in cents to &quot;disappear&quot;, it must become 0 cents, so that adding it doesn't change anything.<br />
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| <br />
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| In both cases, that implies that we're introducing some error into our tunings: Where we would use 3, for instance, we use a number slightly larger or smaller than 3. You can introduce error into any prime, and when tempering out a single comma you can choose to leave any given prime pure. In practice, many people leave 2 pure to achieve pure octaves.<br />
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| <!-- ws:start:WikiTextHeadingRule:0:&lt;h1&gt; --><h1 id="toc0"><a name="Example"></a><!-- ws:end:WikiTextHeadingRule:0 -->Example</h1>
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| The syntonic comma is 81/80. That's 3*3*3*3 / 5*2*2*2*2 or, in monzo form, | -4 4 -1 &gt; .<br />
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| <br />
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| 19 EDO tempers out 81/80. (Technically, we should say that 19 EDO tempers out 81/80 when you use the <a class="wiki_link" href="/patent%20val">patent val</a>.) You can see this in several ways:<br />
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| <br />
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| <!-- ws:start:WikiTextHeadingRule:2:&lt;h2&gt; --><h2 id="toc1"><a name="Example-1. Counting steps of the val"></a><!-- ws:end:WikiTextHeadingRule:2 -->1. Counting steps of the val</h2>
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| Because there are no primes larger than 5 in 81/80, we say it's a 5-limit comma. The 5-limit patent val for 19 EDO is &lt; 19 30 44 |. That means that you add 19 steps of 19 EDO to get to 2/1, 30 steps to get closest to 3/1, and 44 steps to get closest to 5/1.<br />
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| <br />
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| Note that, because this is an EDO, 19 steps gets you precisely to 2/1. We say that 30 steps of 19 EDO gets you to 3/1, but that's only an approximation. Same with 5/1, etc. This is where the error in the primes gets introduced. Don't worry, though, it's very useful error.<br />
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| <br />
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| Getting to 81 is 3*3*3*3, or, with 19 EDO steps, 30+30+30+30 = 120 steps of 19 EDO.<br />
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| Getting to 80 is 5*2*2*2*2, or, with 19 EDO steps, 44+19+19+19+19 = 120 steps of 19 EDO.<br />
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| <br />
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| Getting to 81/80 means adding the steps needed to get to 81, and subtracting the steps needed to get to 80. 120 steps - 120 steps = 0 steps.<br />
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| <br />
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| Applying the monzo to the val (also called getting the &quot;homomorphism&quot;) is easier. Multiply the first number in the monzo (which represents the number of 2/1s in the comma) and by the first number in the val (which represents the number of steps it takes to get to 2/1), then multiply the second number in the monzo by the second number in the val, then the third by the third, and add them all together: (-4 * 19) + (4 * 30) + (-1 * 44) = 0 steps.<br />
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| <br />
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| Therefore, adding 81/80 to any interval in 19 EDO means adding 0 steps of 19 EDO to it. In other words, 81/80 is effectively zero: 81/80 is &quot;tempered out&quot;.<br />
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| <br />
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| <!-- ws:start:WikiTextHeadingRule:4:&lt;h2&gt; --><h2 id="toc2"><a name="Example-2. Painstakingly doing the math"></a><!-- ws:end:WikiTextHeadingRule:4 -->2. Painstakingly doing the math</h2>
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| We say that 30 steps of 19 EDO gets you to 3/1, but, as we say above, that's an error. One step of 19 EDO is the 19th root of 2, or 2^(1/19), or approximately 1.03715504445. (That's 63.15789474 cents.) If you multiply that by itself 19 times, you get exactly 2. But if you multiply that by itself 30 times, you don't get 3: You get 2.98751792330896. Similarly, multiplying it by 44 steps gets you 4.97877035785607 instead of 5.<br />
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| <br />
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| If we plug in these values into 81/80, we see that 81/80 is tempered out:<br />
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| 81/80 = 3*3*3*3 / 5*2*2*2*2 = (3^4) / (5)*(2^4). Substitute our values and you get<br />
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| (2.98751792330896 ^ 4) / (4.97877035785607)*(2^4) <br />
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| = 79.66032573 / (4.97877035785607 * 16) <br />
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| = 79.66032573 / 79.66032573<br />
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| = 1/1.<br />
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| <span style="display: block; height: 1px; left: -40px; overflow: hidden; position: absolute; top: -25px; width: 1px;"><br />
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| | <pre> |
| | 81/80 = 3*3*3*3 / 5*2*2*2*2 = (3^4) / (5)*(2^4). // Substitute our values and you get |
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| | (2.987518 ^ 4) / (4.97877)*(2^4) |
| | = 79.660326 / (4.97877 * 16) |
| | = 79.660326 / 79.660326 |
| | = 1/1 |
| | </pre> |
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| | == See also == |
| | * [[Fudging]] – or ''virtual tempering'' |
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| <table class="wiki_table">
| | == Notes == |
| <tr>
| | <references /> |
| <td>2.98751792330896<br />
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| </td>
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| </tr>
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| </table>
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| </span></body></html></pre></div>
| | [[Category:Regular temperament theory]] |
| | [[Category:Comma]] |
| | [[Category:Method]] |
| | [[Category:Terms]] |