User:Dummy index/Bimetallic MOS - Revision history

Dummy index: /* Generator size */

2023-06-04T12:38:16Z

Generator size

← Older revision		Revision as of 12:38, 4 June 2023
Line 114:		Line 114:
	! !! Dividing ratio !! Generator size !! Remarks		! !! Dividing ratio !! Generator size !! Remarks
	\|-		\|-
	\| Golden \|\| <math>L_1:s_1 = φ-1:1</math> \|\| g = 458.36 ¢, p = 1200 ¢ \|\| logarithmic phi		\| Golden \|\| <math>L_1:s_1 = φ-1:1</math><br /><small>i.e. <math>(s:L = 1:φ)</math></small> \|\| g = 458.36 ¢, p = 1200 ¢ \|\| logarithmic phi
	\|-		\|-
	\| Silver 1st isotope \|\| <math>L_1:s_1 = δ_s-1:1</math> \|\| g = 702.94 ¢, p = 1200 ¢ \|\| argent fifth		\| Silver 1st isotope \|\| <math>L_1:s_1 = δ_s-1:1</math> \|\| g = 702.94 ¢, p = 1200 ¢ \|\| argent fifth
	\|-		\|-
	\| Silver \|\| <math>L_2:s_2 = δ_s-2:1</math> \|\| g = 351.47 ¢, p = 1200 ¢\|\| Imaginary, argent neutral third		\| Silver \|\| <math>L_2:s_2 = δ_s-2:1</math><br /><small>i.e. <math>(s:L = 1:δ_s)</math></small> \|\| g = 351.47 ¢, p = 1200 ¢\|\| Imaginary, argent neutral third
	\|-		\|-
	\| Bimetallic (unnamed A-1) \|\| <math>L_1:s_1 = \sqrt{3}:1</math> \|\| g = 760.77 ¢, p = 1200 ¢ \|\|		\| Bimetallic (unnamed A-1) \|\| <math>L_1:s_1 = \sqrt{3}:1</math> \|\| g = 760.77 ¢, p = 1200 ¢ \|\|
	\|-		\|-
	\| Bimetallic (unnamed A-2) \|\| <math>L_2:s_2 = \sqrt{3}-1:1</math> \|\| g = 507.18 ¢, p = 1200 ¢ \|\| Flattone		\| Bimetallic (unnamed A-2) \|\| <math>L_2:s_2 = \sqrt{3}-1:1</math><br /><small>i.e. <math>(s_3:L_3 = 1:(\sqrt{3}+1)/2)</math></small> \|\| g = 507.18 ¢, p = 1200 ¢ \|\| Flattone
	\|-		\|-
	\| Bimetallic (unnamed A-3) \|\| <math>L_4:s_4 = (\sqrt{3}-1)/2:1</math> \|\| g = 321.54 ¢, p = 1200 ¢ \|\| Superkleismic		\| Bimetallic (unnamed A-3) \|\| <math>L_4:s_4 = (\sqrt{3}-1)/2:1</math><br /><small>i.e. <math>(s:L = 1:\sqrt{3}+1)</math></small> \|\| g = 321.54 ¢, p = 1200 ¢ \|\| Superkleismic
	\|-		\|-
	\| Bimetallic (unnamed B-1) \|\| <math>L_1:s_1 = 2\sqrt{2}+1:1</math> \|\| g = 951.47 ¢, p = 1200 ¢ \|\| Semaphore		\| Bimetallic (unnamed B-1) \|\| <math>L_1:s_1 = 2\sqrt{2}+1:1</math> \|\| g = 951.47 ¢, p = 1200 ¢ \|\| Semaphore
Line 132:		Line 132:
	\| Bimetallic (unnamed B-3) \|\| <math>L_3:s_3 = 2\sqrt{2}-1:1</math> \|\| g = 775.74 ¢, p = 1200 ¢ \|\| Squares		\| Bimetallic (unnamed B-3) \|\| <math>L_3:s_3 = 2\sqrt{2}-1:1</math> \|\| g = 775.74 ¢, p = 1200 ¢ \|\| Squares
	\|-		\|-
	\| Bimetallic (unnamed B-4) \|\| <math>L_4:s_4 = 2\sqrt{2}-2:1</math> \|\| g = 543.70 ¢, p = 1200 ¢ \|\|		\| Bimetallic (unnamed B-4) \|\| <math>L_4:s_4 = 2\sqrt{2}-2:1</math><br /><small>i.e. <math>(s_5:L_5 = 1:(\sqrt{2}+1)/2)</math></small> \|\| g = 543.70 ¢, p = 1200 ¢ \|\|
	\|-		\|-
	\| Bimetallic (unnamed B-5) \|\| <math>L_6:s_6 = (\sqrt{2}-1)/2:1</math> \|\| g = 205.89 ¢, p = 1200 ¢ \|\|		\| Bimetallic (unnamed B-5) \|\| <math>L_6:s_6 = (\sqrt{2}-1)/2:1</math><br /><small>i.e. <math>(s:L = 1:2\sqrt{2}+2)</math></small> \|\| g = 205.89 ¢, p = 1200 ¢ \|\|
	\|}		\|}

Dummy index at 15:21, 2 June 2023

2023-06-02T15:21:00Z

@@ Line 79: / Line 79: @@
 LLsLsLLsLsLs LLsLsLs (from 2nd: 7L 5s, from 3rd: 4L 3s)
 </pre>
 == Generator size ==
 {| class="wikitable"
 !  !! Dividing ratio !! Generator size !! Remarks
 |-
-| Golden || <math>L_1:s_1 = φ-1:1</math> || 458.36 (741.64) \ 1200 || logarithmic phi
+| Golden || <math>L_1:s_1 = φ-1:1</math> || g = 458.36 ¢, p = 1200 ¢ || logarithmic phi
 |-
-| Silver 1st isotope || <math>L_1:s_1 = δ_s-1:1</math> || 702.94 \ 1200 || argent fifth
+| Silver 1st isotope || <math>L_1:s_1 = δ_s-1:1</math> || g = 702.94 ¢, p = 1200 ¢ || argent fifth
 |-
-| Silver || <math>L_2:s_2 = δ_s-2:1</math> || 351.47 \ 1200|| Imaginary, argent neutral third
+| Silver || <math>L_2:s_2 = δ_s-2:1</math> || g = 351.47 ¢, p = 1200 ¢|| Imaginary, argent neutral third
 |-
-| Bimetallic (no name A-1) || <math>L_1:s_1 = \sqrt{3}:1</math> || 760.77 \ 1200 ||
+| Bimetallic (unnamed A-1) || <math>L_1:s_1 = \sqrt{3}:1</math> || g = 760.77 ¢, p = 1200 ¢ ||
 |-
-| Bimetallic (no name A-2) || <math>L_2:s_2 = \sqrt{3}-1:1</math> || 507.18 \ 1200|| Flattone
+| Bimetallic (unnamed A-2) || <math>L_2:s_2 = \sqrt{3}-1:1</math> || g = 507.18 ¢, p = 1200 ¢ || Flattone
 |-
-| Bimetallic (no name A-3) || <math>L_4:s_4 = (\sqrt{3}-1)/2:1</math>  || 321.54 \ 1200|| Superkleismic
+| Bimetallic (unnamed A-3) || <math>L_4:s_4 = (\sqrt{3}-1)/2:1</math> || g = 321.54 ¢, p = 1200 ¢ || Superkleismic
 |}

Dummy index at 14:21, 1 June 2023

2023-06-01T14:21:36Z

← Older revision		Revision as of 14:21, 1 June 2023
Line 46:		Line 46:
	LsLsLss LsLss (from 1st: 5L 7s, from 2nd: 3L 4s)		LsLsLss LsLss (from 1st: 5L 7s, from 2nd: 3L 4s)
	</pre>		</pre>
	== Bimetallic ~~case~~ ==		== Bimetallic cases ==
	First, Imagine <math>L = \sqrt{3}+1</math> and <math>s = 1</math> and divide L into		First, Imagine <math>L = \sqrt{3}+1</math> and <math>s = 1</math> and divide L into

Line 63:		Line 63:
	No, <math>L_4 < s_4</math>. Let new <math>s := L_4</math> and new <math>L := s_4</math>. (Rotate the rectangle 90°)		No, <math>L_4 < s_4</math>. Let new <math>s := L_4</math> and new <math>L := s_4</math>. (Rotate the rectangle 90°)

	OK, now <math>L = \sqrt{3}-1</math> and <math>s = 2-\sqrt{3}</math> and <math>~~L_3~~:~~s_3~~ = \sqrt{3}+1 = [2; 1, 2, 1, 2, ...]</math>.		OK, now <math>L = \sqrt{3}-1</math> and <math>s = 2-\sqrt{3}</math> and <math>L:s = \sqrt{3}+1 = [2; 1, 2, 1, 2, ...]</math>.

	Loop.		Loop.
Line 79:		Line 79:
	LLsLsLLsLsLs LLsLsLs (from 2nd: 7L 5s, from 3rd: 4L 3s)		LLsLsLLsLsLs LLsLsLs (from 2nd: 7L 5s, from 3rd: 4L 3s)
	</pre>		</pre>
			== Generator size ==
			{\| class="wikitable"
			! !! Dividing ratio !! Generator size !! Remarks
			\|-
			\| Golden \|\| <math>L_1:s_1 = φ-1:1</math> \|\| 458.36 (741.64) \ 1200 \|\| logarithmic phi
			\|-
			\| Silver 1st isotope \|\| <math>L_1:s_1 = δ_s-1:1</math> \|\| 702.94 \ 1200 \|\| argent fifth
			\|-
			\| Silver \|\| <math>L_2:s_2 = δ_s-2:1</math> \|\| 351.47 \ 1200\|\| Imaginary, argent neutral third
			\|-
			\| Bimetallic (no name A-1) \|\| <math>L_1:s_1 = \sqrt{3}:1</math> \|\| 760.77 \ 1200 \|\|
			\|-
			\| Bimetallic (no name A-2) \|\| <math>L_2:s_2 = \sqrt{3}-1:1</math> \|\| 507.18 \ 1200\|\| Flattone
			\|-
			\| Bimetallic (no name A-3) \|\| <math>L_4:s_4 = (\sqrt{3}-1)/2:1</math> \|\| 321.54 \ 1200\|\| Superkleismic
			\|}

Dummy index at 14:34, 30 May 2023

2023-05-30T14:34:52Z

← Older revision		Revision as of 14:34, 30 May 2023
Line 1:		Line 1:
	See [[Metallic MOS]]. The article is ~~uncomfortable~~ with the definition of the split operation, so ~~I'll~~ write it in my own way.		See [[Metallic MOS]]. The article is unelegant with the definition of the split operation, so l write it in my own way.

	== Golden case ==		== Golden case ==
	You know a process cutting ~~the~~ square from golden rectangle. Imagine <math>L = φ</math> and <math>s = 1</math> and divide L into		You know a process cutting off a square from a golden rectangle. Imagine <math>L = φ</math> and <math>s = 1</math> and divide L into

	<math>\qquad L_1:s_1 = φ-1:1 = [0; 1, 1, 1, 1, ...]</math>.		<math>\qquad L_1:s_1 = φ-1:1 = [0; 1, 1, 1, 1, ...]</math>.

	No, <math>L_1 < s_1</math>. Let new <math>s := L_1</math> and new <math>L = s_1</math>. (Rotate the rectangle 90°)		No, <math>L_1 < s_1</math>. Let new <math>s := L_1</math> and new <math>L := s_1</math>. (Rotate the rectangle 90°)

	OK, now <math>L = 1</math> and <math>s = φ-1</math> and <math>L:s = φ</math>.		OK, now <math>L = 1</math> and <math>s = φ-1</math> and <math>L:s = φ = [1; 1, 1, 1, 1, ...]</math>.

	Loop.		Loop.

	In thinking MOS pattern, direction of division is altered when every ~~rotating~~.		In thinking MOS pattern, direction of division is altered when every rotation.

	<pre>L		<pre>L
Line 30:		Line 30:
	<math>\qquad L_2:s_2 = δ_s-2:1 = [0; 2, 2, 2, 2, ...]</math>.		<math>\qquad L_2:s_2 = δ_s-2:1 = [0; 2, 2, 2, 2, ...]</math>.

	No, <math>L_2 < s_2</math>. Let new <math>s := L_2</math> and new <math>L = s_2</math>. (Rotate the rectangle 90°)		No, <math>L_2 < s_2</math>. Let new <math>s := L_2</math> and new <math>L := s_2</math>. (Rotate the rectangle 90°)

	OK, now <math>L = 1</math> and <math>s = δ_s-2</math> and <math>L:s = δ_s</math>.		OK, now <math>L = 1</math> and <math>s = δ_s-2</math> and <math>L:s = δ_s = [2; 2, 2, 2, 2, ...]</math>.

	Loop.		Loop.
Line 40:		Line 40:
	* Let L<sub>1</sub> = period and divide L<sub>1</sub>.		* Let L<sub>1</sub> = period and divide L<sub>1</sub>.
	<pre>L (first entry point)		<pre>L (first entry point)
	L s (second entry point)		L s (left: second entry point)
	sL L		sL L
	ssL sL (from 1st: 2L 3s, from 2nd: 1L 2s)		ssL sL (from 1st: 2L 3s, from 2nd: 1L 2s)
Line 46:		Line 46:
	LsLsLss LsLss (from 1st: 5L 7s, from 2nd: 3L 4s)		LsLsLss LsLss (from 1st: 5L 7s, from 2nd: 3L 4s)
	</pre>		</pre>
	== ~~Bimetal~~ case ==		== Bimetallic case ==
			First, Imagine <math>L = \sqrt{3}+1</math> and <math>s = 1</math> and divide L into

			<math>\qquad L_1:s_1 = \sqrt{3}:1 = [1; 1, 2, 1, 2, ...]</math>.

			OK, now <math>L_1 = \sqrt{3}</math> and <math>s_1 = s = 1</math>. Next, divide L<sub>1</sub> into

			<math>\qquad L_2:s_2 = \sqrt{3}-1:1 = [0; 1, 2, 1, 2, ...]</math>.

			No, <math>L_2 < s_2</math>. Let <math>s_3 := L_2</math> and <math>L_3 := s_2</math>. (Rotate the rectangle 90°)

			OK, now <math>L_3 = 1</math> and <math>s_3 = \sqrt{3}-1</math> and <math>L_3:s_3 = (\sqrt{3}+1) / 2 = [1; 2, 1, 2, 1, ...]</math>. Next, divide L<sub>3</sub> into

			<math>\qquad L_4:s_4 = (\sqrt{3}-1)/2:1 = [0; 2, 1, 2, 1, ...]</math>.

			No, <math>L_4 < s_4</math>. Let new <math>s := L_4</math> and new <math>L := s_4</math>. (Rotate the rectangle 90°)

			OK, now <math>L = \sqrt{3}-1</math> and <math>s = 2-\sqrt{3}</math> and <math>L_3:s_3 = \sqrt{3}+1 = [2; 1, 2, 1, 2, ...]</math>.

			Loop.

			In this case, we actually can choose from three entry points:
			* Let L = period and divide L, or
			* Let L<sub>1</sub> = period and divide L<sub>1</sub>, or
			* Let L<sub>3</sub> = period and divide L<sub>3</sub>.
			<pre>L (first entry point)
			L s (left: second entry point)
			sL L (right: third entry point)
			LLs Ls (from 1st: 3L 2s, from 2nd: 2L 1s)
			LsLss Lss (from 1st: 3L 5s, from 2nd: 2L 3s, from 3rd: 1L 2s)
			sLLsLLL sLLL (from 1st: 8L 3s, from 2nd: 5L 2s, from 3rd: 3L 1s)
			LLsLsLLsLsLs LLsLsLs (from 2nd: 7L 5s, from 3rd: 4L 3s)
			</pre>

Dummy index: Created page with "See Metallic MOS. The article is uncomfortable with the definition of the split operation, so I'll write it in my own way. == Golden case == You know a process cutting th..."

2023-05-29T14:37:37Z

Created page with "See Metallic MOS. The article is uncomfortable with the definition of the split operation, so I'll write it in my own way. == Golden case == You know a process cutting th..."

New page

See [[Metallic MOS]]. The article is uncomfortable with the definition of the split operation, so I'll write it in my own way.

== Golden case ==
You know a process cutting the square from golden rectangle. Imagine <math>L = φ</math> and <math>s = 1</math> and divide L into

<math>\qquad L_1:s_1 = φ-1:1 = [0; 1, 1, 1, 1, ...]</math>.

No, <math>L_1 < s_1</math>. Let new <math>s := L_1</math> and new <math>L = s_1</math>. (Rotate the rectangle 90°)

OK, now <math>L = 1</math> and <math>s = φ-1</math> and <math>L:s = φ</math>.

Loop.

In thinking MOS pattern, direction of division is altered when every rotating.

<pre>L
sL
LLs (2L 1s)
sLsLL (3L 2s)
LLsLLsLs (5L 3s)
sLsLLsLsLLsLL (8L 5s)
</pre>
== Silver case ==
First, Imagine <math>L = δ_s</math> and <math>s = 1</math> and divide L into

<math>\qquad L_1:s_1 = δ_s-1:1 = [1; 2, 2, 2, 2, ...]</math>.

OK, now <math>L_1 = δ_s-1</math> and <math>s_1 = s = 1</math>. Next, divide L1 into

<math>\qquad L_2:s_2 = δ_s-2:1 = [0; 2, 2, 2, 2, ...]</math>.

No, <math>L_2 < s_2</math>. Let new <math>s := L_2</math> and new <math>L = s_2</math>. (Rotate the rectangle 90°)

OK, now <math>L = 1</math> and <math>s = δ_s-2</math> and <math>L:s = δ_s</math>.

Loop.

In this case, we actually can choose from two entry points:
* Let L = period and divide L, or
* Let L1 = period and divide L1.
<pre>L (first entry point)
L s (second entry point)
sL L
ssL sL (from 1st: 2L 3s, from 2nd: 1L 2s)
LLLs LLs (from 1st: 5L 2s, from 2nd: 3L 1s)
LsLsLss LsLss (from 1st: 5L 7s, from 2nd: 3L 4s)
</pre>
== Bimetal case ==