Talk:K*N subgroups - Revision history

Dummy index at 14:07, 23 June 2024

2024-06-23T14:07:04Z

← Older revision		Revision as of 14:07, 23 June 2024
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	Ah, before that, 5-limit 24edo is enfactored... Sorry.		Ah, before that, 5-limit 24edo is enfactored... Sorry.
	--[[User:Dummy index\|Dummy index]] ([[User talk:Dummy index\|talk]]) 14:55, 13 June 2024 (UTC)		--[[User:Dummy index\|Dummy index]] ([[User talk:Dummy index\|talk]]) 14:55, 13 June 2024 (UTC)

			New example, 5-limit 919 subgroup of 19edo. Because 3 and 5 are equally flattened on 19edo, patent val of 171edo maps these to 1\171 sharpened than intervals of 19edo, respectively. i=1 and i=2 result in intervals {{(}}1/1{{)}}(2^n), its subgroup is 2-limit. Add commas (such as unimodular basis) then we gain only 2.3^171.3^85 subgroup. In this case we need at least i=5, {{(}}1/1, 3^55^4, 3^45^5{{)}} then we gain 2.3^9.3^85 subgroup. And of course, in 3-limit, we need i=9 to gain 2.3^9 subgroup. --[[User:Dummy index\|Dummy index]] ([[User talk:Dummy index\|talk]]) 14:07, 23 June 2024 (UTC)

Dummy index at 14:57, 13 June 2024

2024-06-13T14:57:19Z

← Older revision		Revision as of 14:57, 13 June 2024
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	<q>When two successive values i and i+1 lead to the same normal list</q>		<q>When two successive values i and i+1 lead to the same normal list</q>

	This may cause termination too early. For example... 5-limit 3*24 subgroup of 24edo, I want a result "2.3.125 subgroup", but no additional base at i=2, cause terminating the algorithm and result in "2.3 subgroup". Simply it should be do up to i=k.		This may cause termination too early. For example... 5-limit 3*24 subgroup of 24edo, I want a result "2.3.125 subgroup", but no additional base at i=2, cause terminating the algorithm and result in "2.3 subgroup". Simply it should be do up to i=k.
	--[[User:Dummy index\|Dummy index]] ([[User talk:Dummy index\|talk]]) 13:29, 13 June 2024 (UTC)		--[[User:Dummy index\|Dummy index]] ([[User talk:Dummy index\|talk]]) 13:29, 13 June 2024 (UTC)

	Hmm, subgroup may be extended by this → <q>add to that a basis for the commas of the k*N patent val</q>		Hmm, subgroup may be extended by this → <q>add to that a basis for the commas of the k*N patent val</q>

	Commas are all unison, 0 is divisible by k, not intrusive.		Commas are all unison, 0 is divisible by k, not intrusive.
	Ah, before that, 5-limit 24edo is enfactored... Sorry. --[[User:Dummy index\|Dummy index]] ([[User talk:Dummy index\|talk]]) 14:55, 13 June 2024 (UTC)		Ah, before that, 5-limit 24edo is enfactored... Sorry.
			--[[User:Dummy index\|Dummy index]] ([[User talk:Dummy index\|talk]]) 14:55, 13 June 2024 (UTC)

Dummy index at 14:55, 13 June 2024

2024-06-13T14:55:03Z

← Older revision		Revision as of 14:55, 13 June 2024
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	This may cause termination too early. For example... 5-limit 3*24 subgroup of 24edo, I want a result "2.3.125 subgroup", but no additional base at i=2, cause terminating the algorithm and result in "2.3 subgroup". Simply it should be do up to i=k.		This may cause termination too early. For example... 5-limit 3*24 subgroup of 24edo, I want a result "2.3.125 subgroup", but no additional base at i=2, cause terminating the algorithm and result in "2.3 subgroup". Simply it should be do up to i=k.
	--[[User:Dummy index\|Dummy index]] ([[User talk:Dummy index\|talk]]) 13:29, 13 June 2024 (UTC)		--[[User:Dummy index\|Dummy index]] ([[User talk:Dummy index\|talk]]) 13:29, 13 June 2024 (UTC)
			Hmm, subgroup may be extended by this → <q>add to that a basis for the commas of the k*N patent val</q>
			Commas are all unison, 0 is divisible by k, not intrusive.
			Ah, before that, 5-limit 24edo is enfactored... Sorry. --[[User:Dummy index\|Dummy index]] ([[User talk:Dummy index\|talk]]) 14:55, 13 June 2024 (UTC)

Dummy index: /* Termination condition */ new section

2024-06-13T13:29:51Z

Termination condition: new section

← Older revision		Revision as of 13:29, 13 June 2024
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	{{WSArchiveLink}}		{{WSArchiveLink}}

			== Termination condition ==

			<q>When two successive values i and i+1 lead to the same normal list</q>
			This may cause termination too early. For example... 5-limit 3*24 subgroup of 24edo, I want a result "2.3.125 subgroup", but no additional base at i=2, cause terminating the algorithm and result in "2.3 subgroup". Simply it should be do up to i=k.
			--[[User:Dummy index\|Dummy index]] ([[User talk:Dummy index\|talk]]) 13:29, 13 June 2024 (UTC)

Mike Battaglia: 1 revision imported: Moving archived Wikispaces discussion to subpage

2018-10-01T18:02:37Z

1 revision imported: Moving archived Wikispaces discussion to subpage

← Older revision	Revision as of 18:02, 1 October 2018
(No difference)

WikispacesArchive>Mike Battaglia: Text replacement - "'''All discussion below is archived from the Wikispaces export in its original unaltered form.'''" to "'''All discussion below is archived from the Wikispaces export in its original unaltered form.''' ''...

2018-10-01T18:01:16Z

Text replacement - "'''All discussion below is archived from the Wikispaces export in its original unaltered form.'''" to "'''All discussion below is archived from the Wikispaces export in its original unaltered form.''' <span style="color:#800000">''...

← Older revision		Revision as of 18:01, 1 October 2018
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	~~= ARCHIVED WIKISPACES DISCUSSION BELOW =~~		{{WSArchiveLink}}
	~~'''All discussion below is archived from the Wikispaces export in its original unaltered form.'''~~

	~~<span style="color:#800000">'''PLEASE MAKE ANY NEW COMMENTS <u>ABOVE</u> THIS SECTION.'''</span> Anything below here is for archival purposes only.~~

	~~----~~

	~~== example ==~~
	~~Hello Gene Ward Smith,~~

	~~can you please give a simple example? Thanks :)~~

	~~- '''xenwolf''' May 29, 2011, 12:42:46 PM UTC-0700~~
	~~----~~
	Basically, you take the val of kN-edo, get the primes with mappings divisible by k (integer steps of N-edo), and for those that don't, find some power, product, or quotient that does. For the 2N subgroup you'll usually square the first prime mapped to an odd number of 2N-edo steps and multiply the prime by any other prime mapped to an odd number of steps of 2N-edo.

	~~- '''bootmii''' December 22, 2016, 04:30:17 PM UTC-0800~~
	~~----~~

Mike Battaglia: Text replacement - "'''All discussion below is archived from the Wikispaces export in its original unaltered form.'''" to "'''All discussion below is archived from the Wikispaces export in its original unaltered form.''' ''...

2018-09-20T07:00:39Z

← Older revision		Revision as of 07:00, 20 September 2018
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	= ARCHIVED WIKISPACES DISCUSSION BELOW =		= ARCHIVED WIKISPACES DISCUSSION BELOW =
	'''All discussion below is archived from the Wikispaces export in its original unaltered form.'''		'''All discussion below is archived from the Wikispaces export in its original unaltered form.'''

			<span style="color:#800000">'''PLEASE MAKE ANY NEW COMMENTS <u>ABOVE</u> THIS SECTION.'''</span> Anything below here is for archival purposes only.

	----		----

Wikispaces>FREEZE at 00:00, 17 July 2018

2018-07-17T00:00:00Z

New page

= ARCHIVED WIKISPACES DISCUSSION BELOW =
'''All discussion below is archived from the Wikispaces export in its original unaltered form.'''
----

== example ==
Hello Gene Ward Smith,

can you please give a simple example? Thanks :)

- '''xenwolf''' May 29, 2011, 12:42:46 PM UTC-0700
----
Basically, you take the val of k*N-edo, get the primes with mappings divisible by k (integer steps of N-edo), and for those that don't, find some power, product, or quotient that does. For the 2*N subgroup you'll usually square the first prime mapped to an odd number of 2*N-edo steps and multiply the prime by any other prime mapped to an odd number of steps of 2*N-edo.

- '''bootmii''' December 22, 2016, 04:30:17 PM UTC-0800
----