Skip fretting system 90 5 17 - Revision history

BudjarnLambeth: Links

2025-04-27T04:50:31Z

Links

← Older revision		Revision as of 04:50, 27 April 2025
Line 1:		Line 1:
	One can play in ~~90-edo~~ on an ~~18-edo~~ guitar, by tuning the strings 17\90 (226 and 2/3 cents) apart. The resulting system allows a player to reach any 13-limit interval by crossing a maximum of only 4 frets. ~~Octaves~~ lie across six open strings and one fret, or on the same string 18 frets up (because 90 is divisible by 18).		One can play in [[90edo]] on an [[18edo]] [[guitar]], by tuning the strings 17\90- (226 and 2/3 [[cents]]- ) apart. The resulting system allows a player to reach any [[13-limit]] interval by crossing a maximum of only 4 frets. [[Octave]]s lie across six open strings and one fret, or on the same string 18 frets up (because 90 is divisible by 18).

	For string players, a drawback of this system is that harmonics 3, 7 and 13 all lie on the same string, so only one of them can be played at a time. (For keyboardists this is irrelevant, as all three notes can be played simultaneously.)		For string players, a drawback of this system is that harmonics 3, 7 and 13 all lie on the same string, so only one of them can be played at a time. (For keyboardists this is irrelevant, as all three notes can be played simultaneously.)

Xenwolf: add category

2021-05-05T07:19:28Z

add category

← Older revision		Revision as of 07:19, 5 May 2021
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	\|86 steps = 31 % 16		\|86 steps = 31 % 16
	\|string 3 fret 7		\|string 3 fret 7
	\|}From these, the location of any compound interval can be added by vector-summing the string-fret positions of the interval's factors. See [[Skip fretting system 48 2 13]] for details on how that's done.		\|}

			From these, the location of any compound interval can be added by vector-summing the string-fret positions of the interval's factors. See [[Skip fretting system 48 2 13]] for details on how that's done.

			[[Category:Skip fretting]]

Jeff Brown: point out the drawback only applies to string players

2021-05-04T16:17:48Z

point out the drawback only applies to string players

← Older revision		Revision as of 16:17, 4 May 2021
Line 1:		Line 1:
	One can play in 90-edo on an 18-edo guitar, by tuning the strings 17\90 (226 and 2/3 cents) apart. The resulting system allows a player to reach any 13-limit interval by crossing a maximum of only 4 frets. Octaves lie across six open strings and one fret, or on the same string 18 frets up (because 90 is divisible by 18).		One can play in 90-edo on an 18-edo guitar, by tuning the strings 17\90 (226 and 2/3 cents) apart. The resulting system allows a player to reach any 13-limit interval by crossing a maximum of only 4 frets. Octaves lie across six open strings and one fret, or on the same string 18 frets up (because 90 is divisible by 18).

	A drawback of this system is that harmonics 3, 7 and 13 all lie on the same string, so only one of them can be played at a time.		For string players, a drawback of this system is that harmonics 3, 7 and 13 all lie on the same string, so only one of them can be played at a time. (For keyboardists this is irrelevant, as all three notes can be played simultaneously.)

	The primes intervals lie in the following places:		The primes intervals lie in the following places:

Jeff Brown: Point out a drawback

2021-05-04T15:27:41Z

Point out a drawback

← Older revision		Revision as of 15:27, 4 May 2021
Line 1:		Line 1:
	One can play in 90-edo on an 18-edo guitar, by tuning the strings 17\90 (226 and 2/3 cents) apart. The resulting system allows a player to reach any 13-limit interval by crossing a maximum of only 4 frets. Octaves lie across six open strings and one fret, or on the same string 18 frets up (because 90 is divisible by 18).		One can play in 90-edo on an 18-edo guitar, by tuning the strings 17\90 (226 and 2/3 cents) apart. The resulting system allows a player to reach any 13-limit interval by crossing a maximum of only 4 frets. Octaves lie across six open strings and one fret, or on the same string 18 frets up (because 90 is divisible by 18).

			A drawback of this system is that harmonics 3, 7 and 13 all lie on the same string, so only one of them can be played at a time.

	The primes intervals lie in the following places:		The primes intervals lie in the following places:

Jeff Brown: start

2021-05-04T15:12:29Z

start

New page

One can play in 90-edo on an 18-edo guitar, by tuning the strings 17\90 (226 and 2/3 cents) apart. The resulting system allows a player to reach any 13-limit interval by crossing a maximum of only 4 frets. Octaves lie across six open strings and one fret, or on the same string 18 frets up (because 90 is divisible by 18).

The primes intervals lie in the following places:
{| class="wikitable"
!note
!fretboard position
|-
|0 steps = 1 % 1
|string 0 fret 0
|-
|90 steps = 2 % 1
|string 5 fret 1
|-
|53 steps = 3 % 2
|string 4 fret - 3
|-
|29 steps = 5 % 4
|string 2 fret - 1
|-
|73 steps = 7 % 4
|string 4 fret 1
|-
|41 steps = 11 % 8
|string 3 fret - 2
|-
|63 steps = 13 % 8
|string 4 fret - 1
|-
|8 steps = 17 % 16
|string - 1 fret 5
|-
|22 steps = 19 % 16
|string 1 fret 1
|-
|47 steps = 23 % 16
|string 1 fret 6
|-
|77 steps = 29 % 16
|string 1 fret 12
|-
|86 steps = 31 % 16
|string 3 fret 7
|}From these, the location of any compound interval can be added by vector-summing the string-fret positions of the interval's factors. See [[Skip fretting system 48 2 13]] for details on how that's done.